Integrand size = 23, antiderivative size = 94 \[ \int \frac {a+b \tan (e+f x)}{(d \sec (e+f x))^{3/2}} \, dx=-\frac {2 b}{3 f (d \sec (e+f x))^{3/2}}+\frac {2 a \sqrt {\cos (e+f x)} \operatorname {EllipticF}\left (\frac {1}{2} (e+f x),2\right ) \sqrt {d \sec (e+f x)}}{3 d^2 f}+\frac {2 a \sin (e+f x)}{3 d f \sqrt {d \sec (e+f x)}} \]
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Time = 0.08 (sec) , antiderivative size = 94, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.174, Rules used = {3567, 3854, 3856, 2720} \[ \int \frac {a+b \tan (e+f x)}{(d \sec (e+f x))^{3/2}} \, dx=\frac {2 a \sqrt {\cos (e+f x)} \operatorname {EllipticF}\left (\frac {1}{2} (e+f x),2\right ) \sqrt {d \sec (e+f x)}}{3 d^2 f}+\frac {2 a \sin (e+f x)}{3 d f \sqrt {d \sec (e+f x)}}-\frac {2 b}{3 f (d \sec (e+f x))^{3/2}} \]
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Rule 2720
Rule 3567
Rule 3854
Rule 3856
Rubi steps \begin{align*} \text {integral}& = -\frac {2 b}{3 f (d \sec (e+f x))^{3/2}}+a \int \frac {1}{(d \sec (e+f x))^{3/2}} \, dx \\ & = -\frac {2 b}{3 f (d \sec (e+f x))^{3/2}}+\frac {2 a \sin (e+f x)}{3 d f \sqrt {d \sec (e+f x)}}+\frac {a \int \sqrt {d \sec (e+f x)} \, dx}{3 d^2} \\ & = -\frac {2 b}{3 f (d \sec (e+f x))^{3/2}}+\frac {2 a \sin (e+f x)}{3 d f \sqrt {d \sec (e+f x)}}+\frac {\left (a \sqrt {\cos (e+f x)} \sqrt {d \sec (e+f x)}\right ) \int \frac {1}{\sqrt {\cos (e+f x)}} \, dx}{3 d^2} \\ & = -\frac {2 b}{3 f (d \sec (e+f x))^{3/2}}+\frac {2 a \sqrt {\cos (e+f x)} \operatorname {EllipticF}\left (\frac {1}{2} (e+f x),2\right ) \sqrt {d \sec (e+f x)}}{3 d^2 f}+\frac {2 a \sin (e+f x)}{3 d f \sqrt {d \sec (e+f x)}} \\ \end{align*}
Time = 0.70 (sec) , antiderivative size = 69, normalized size of antiderivative = 0.73 \[ \int \frac {a+b \tan (e+f x)}{(d \sec (e+f x))^{3/2}} \, dx=-\frac {\sqrt {d \sec (e+f x)} \left (b+b \cos (2 (e+f x))-2 a \sqrt {\cos (e+f x)} \operatorname {EllipticF}\left (\frac {1}{2} (e+f x),2\right )-a \sin (2 (e+f x))\right )}{3 d^2 f} \]
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Result contains complex when optimal does not.
Time = 10.85 (sec) , antiderivative size = 155, normalized size of antiderivative = 1.65
method | result | size |
default | \(\frac {\frac {2 i F\left (i \left (\cot \left (f x +e \right )-\csc \left (f x +e \right )\right ), i\right ) \sqrt {\frac {\cos \left (f x +e \right )}{\cos \left (f x +e \right )+1}}\, \sqrt {\frac {1}{\cos \left (f x +e \right )+1}}\, a}{3}+\frac {2 i \sec \left (f x +e \right ) F\left (i \left (\cot \left (f x +e \right )-\csc \left (f x +e \right )\right ), i\right ) \sqrt {\frac {\cos \left (f x +e \right )}{\cos \left (f x +e \right )+1}}\, \sqrt {\frac {1}{\cos \left (f x +e \right )+1}}\, a}{3}+\frac {2 \sin \left (f x +e \right ) a}{3}-\frac {2 b \cos \left (f x +e \right )}{3}}{d f \sqrt {d \sec \left (f x +e \right )}}\) | \(155\) |
parts | \(-\frac {2 a \left (i \sqrt {\frac {\cos \left (f x +e \right )}{\cos \left (f x +e \right )+1}}\, F\left (i \left (\csc \left (f x +e \right )-\cot \left (f x +e \right )\right ), i\right ) \sqrt {\frac {1}{\cos \left (f x +e \right )+1}}+i \sec \left (f x +e \right ) \sqrt {\frac {\cos \left (f x +e \right )}{\cos \left (f x +e \right )+1}}\, F\left (i \left (\csc \left (f x +e \right )-\cot \left (f x +e \right )\right ), i\right ) \sqrt {\frac {1}{\cos \left (f x +e \right )+1}}-\sin \left (f x +e \right )\right )}{3 f \sqrt {d \sec \left (f x +e \right )}\, d}-\frac {2 b}{3 f \left (d \sec \left (f x +e \right )\right )^{\frac {3}{2}}}\) | \(162\) |
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Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 0.09 (sec) , antiderivative size = 103, normalized size of antiderivative = 1.10 \[ \int \frac {a+b \tan (e+f x)}{(d \sec (e+f x))^{3/2}} \, dx=\frac {-i \, \sqrt {2} a \sqrt {d} {\rm weierstrassPInverse}\left (-4, 0, \cos \left (f x + e\right ) + i \, \sin \left (f x + e\right )\right ) + i \, \sqrt {2} a \sqrt {d} {\rm weierstrassPInverse}\left (-4, 0, \cos \left (f x + e\right ) - i \, \sin \left (f x + e\right )\right ) - 2 \, {\left (b \cos \left (f x + e\right )^{2} - a \cos \left (f x + e\right ) \sin \left (f x + e\right )\right )} \sqrt {\frac {d}{\cos \left (f x + e\right )}}}{3 \, d^{2} f} \]
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\[ \int \frac {a+b \tan (e+f x)}{(d \sec (e+f x))^{3/2}} \, dx=\int \frac {a + b \tan {\left (e + f x \right )}}{\left (d \sec {\left (e + f x \right )}\right )^{\frac {3}{2}}}\, dx \]
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\[ \int \frac {a+b \tan (e+f x)}{(d \sec (e+f x))^{3/2}} \, dx=\int { \frac {b \tan \left (f x + e\right ) + a}{\left (d \sec \left (f x + e\right )\right )^{\frac {3}{2}}} \,d x } \]
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\[ \int \frac {a+b \tan (e+f x)}{(d \sec (e+f x))^{3/2}} \, dx=\int { \frac {b \tan \left (f x + e\right ) + a}{\left (d \sec \left (f x + e\right )\right )^{\frac {3}{2}}} \,d x } \]
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Timed out. \[ \int \frac {a+b \tan (e+f x)}{(d \sec (e+f x))^{3/2}} \, dx=\int \frac {a+b\,\mathrm {tan}\left (e+f\,x\right )}{{\left (\frac {d}{\cos \left (e+f\,x\right )}\right )}^{3/2}} \,d x \]
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